0=x^2+18x+17

Solution for 0=x^2+18x+17 equation:

0=x^2+18x+17

We move all terms to the left:

0-(x^2+18x+17)=0

We add all the numbers together, and all the variables

-(x^2+18x+17)=0

We get rid of parentheses

-x^2-18x-17=0

We add all the numbers together, and all the variables

-1x^2-18x-17=0

a = -1; b = -18; c = -17;
Δ = b2-4ac
Δ = -182-4·(-1)·(-17)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-16}{2*-1}=\frac{2}{-2}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+16}{2*-1}=\frac{34}{-2}
=-17
$